Page 99 - Electrician -1st Year - TT

= (V x I) x t
Fig 3
E = V x I x t
ªu]ôt\Xõu AXÏ "Yôh aYo' BÏm.
(“Watt hour” )(Wh) ªu]ôt\Xõu ®tTû] AXÏ
(commercial unit) "¡úXô Yôh aYo' ApXÕ
"ë²h' BÏm. (“Kilo watt hour” (KWH) or unit)

RWlThPÕ B.O.T (úTôoÓ B@l ¥úWÓ) ë²h (KWH/
Unit) B.O.T (Board of Trade) unit / KWH/Unit
V = 1.5 V
R = 1 K JÚ 1000 Yôh ªu ®[dûL JÚ U¦ úSWm
ùRôPokÕ TVuTÓj§]ôp ùNXYô]
V ªu]ôt\ûX JÚ B.O.T (Board of Trade) ë²h
I =
R Guß YûWVßdLlTÓ¡\Õ. AkR ®[d¡p
JÚ ¡úXô Yôh aYo (1kWH) ªu]ôt\p
1.5
I = = 0.0015 amp. ùNXYô¡\Õ. CÕ ë²h Gußm
1000
AûZdLlTÓ¡\Õ.
ªu Nd§ (P) Utßm ªu]ôt\p (E) ªu]ôt\p = 1000W x 1Hr = 1000WH (or) 1kWH
Electrical power (P) & Energy (E) : ªu]ÝjRm (V)
ERôWQm 1 (Example 1) : JÚ 750W/250V
Utßm ªuú]ôhPjûR (I) ùTÚd¡ A§p
¡ûPdÏm A[ûY ªuNd§ Guß ªuNôW Cv§¬ùTh¥ûV 90 ¨ªPeLÞdÏ
ùRôPokÕ TVuTÓj§]ôp ùNXYôÏm
AûZdLlTÓ¡\Õ.
ªu]ôt\ûX LQd¡PÜm.
ªuNd§ (Electrical power) (P) = ªu]ÝjRm x
ùLôÓdLlThPÕ (Given):
ªuú]ôhPm
P=V x I ªuNd§ (P) = 750W
ªu]ÝjRm (V) = 250V
ªuNd§«u AXÏ "Yôh' (‘Watt’). CÕ ‘P’ Gu\
Be¡X GÝjRôp ϱl©PlTÓ¡\Õ. Yôh úSWm = 90 ¨ªPeLs
ÁhPûW (Watt meter) TVuTÓj§ ªuNd§ûV ApXÕ 1.5 U¦
A[®PXôm. ªuNd§ ãj§Wj§XõÚkÕ
LiÓ©¥dLÜm (Find):
¸rLiP ãj§WeLû[ YûWVßdLXôm.
ªu]ôt\p (E) = ?
i P = V X I
= IR x I ¾oÜ (Solution):

P= I R ªu]ôt\p (E) = P x t
2
ii P = V X I = 750 w x 1.5Hr
= 1125 WH (or)
V
= Vx E = 1.125 kWH
R
Jod, TYo Utßm G]o_õ (Work, Power and
2
V Energy) : JÚ ®ûN (force) JÚ ùTôÚû[ Ko
P =
R CPj§XõÚkÕ Utù\ôÚ CPj§tÏ
SLoj§]ôp AûR Jod (Work) Guß
ªu]ôt\p (Electrical Energy) (E) : ªuNd§ (P) áß¡uú\ôm.
Utßm úSWm (t) B¡V CWiûPÙm ùTÚd¡
A§p ¡ûPdÏm A[ûY ªu]ôt\p (electrical Jod (Work) = ®ûN (Force) x SLokR çWm
energy) Guß AûZdLlTÓ¡\Õ. w.d = F x S
ªu]ôt\p = ªuNd§ x úSWm ùTôÕYôL CÕ “W” Gu\ GÝjRôp
Electrical Energy (E) = Power x time ϱl©PlTÓ¡\Õ.

E = P x t i Jod¡u (Work) AXÏ (unit ) (F.P.S) £vPj§p
(Foot Pound Second) BÏm.
ªuT¦Vô[o þ (NSQF: ¨ûX- 5) T«t£ 1.4.34 dLô] ùRôPo×d LÚj§Vp 79