Page 388 - Electrician -1st Year - TT
P. 388
âù«õ, ÞF™ N ñŸÁ‹ N â¡ð¶ ©ûWU¬ ñŸÁ‹
1 2
E = 4.44 f N ø ...(4) ùNLiP¬ ûY«u¥e ²ŸÁ‚èO¡
1 1 m
â‡E‚¬è º¬ø«òò£°‹.
ñŸÁ‹
E = 4.44 f N ø ...(5)
2 2 m
¥Wôuv@TôoUo þ G°ûUVô] LQdÏLs (Transformer - simple calculations)
úSôdLeLs: ClTôPj§u Ø¥®p ¿eLs ùT\ úYi¥V A±Ü §\uLs
• ¥Wôuv@TôoUo úWh¥eûLl Tt± ®[dÏRp
• ùNLiP¬«u úPhPô®≠ÚkÕ ©ûWU¬«u ªu]ÝjRm, ªuú]ôhPm, ÑtßLû[
LQd¡ÓRp.
¥Wôuv@TôoU¬u úWh¥e (Rating of trans- ùR¬kRûY
former) : ¥WôuvTôm¬u §\u GlùTôÝÕm E = (4.44 x f x N x ) volts
ARu AlúTWuh TYo (volt amp - VA) (or KVA) P P m
þ¬p ϱl©PlTÓ¡\Õ. EiûUVô] TY¬p V P = I S ≅ E P ≅ N P
(watt (or) KW) (ie.) KW = KVA x Cos V S I P E S N S
ERôWQm 1 (Example 1) : JÚ 100 KVA 2400/ V I = V I = KVA
P P S S
240V, 50 Hz ¥Wôuv@TôoU¬p ùNLiP¬
¾oÜ (Solution)
ÑtßdL°u Gi¦dûL 300 ÑtßLs
¸rLiPYtû\ LQd¡ÓL. (a) úRôWôVUôL KVA × 1000 100000
(a) I (full load) = = = 41.7A
©ûWU¬ Utßm ùNLiP¬«u P V p 2400
ªuú]ôhPm (b) ùNLiP¬ ÑtßLs (c) 100000
¥Wôuv@TôoU¬u úLô¬p HtTÓm EVokR and I S = = 417A
240
ThN LôkRdúLôÓL°u Gi¦dûLûV V 2400 N
(b) P = = 10 = P
LQd¡ÓL. V S 240 N S
ùLôÓdLlThP ®YWm
Therefore, N = 10 x N
P S
¥Wôuv@TôoUo A[Ü = 100 KVA = 10 x 300 = 3000 turns.
(c) 4.44 x f x N x = E
@©¬dÏYu£ (f) = 50 Hz P m P
2400
©ûWU¬ ªu]ÝjRm (V ) = 2400 V Φ = = 0.0036 Wb.
P m 4.44 × 50 × 3000
ùNLiP¬ ªu]ÝjRm (V ) = 240 V
S
ùNLiP¬ ÑtßLs (N ) = 300
S
¥Wôuv@TôoU¬u YûLLs (Classification of transformer)
úSôdLeLs: ClTôPj§u Ø¥®p ¿eLs ùT\ úYi¥V A±Ü §\uLs
• TpúYß LôW¦Lû[ A¥lTûPVôLd ùLôiÓ ¥Wôuv@TôoUoLû[
YûLlTÓjÕRp
• EXokR YûL ¥Wôuv@TôoUoLû[ áßRp.
¥Wôuv@TôoUoL°u YûLLs (Classifi- LôkRj §\]t\ úLôûW ùLôi¥ÚdÏm.
cation of Transformers) CRu ÁÕ ©ûWU¬ Utßm ùNLiP¬
1 úLô¬p TVuTÓjRlTÓm ùTôÚû[ Ñt\lTh¥ÚdÏm. LôkR EúXôLm C§p
A¥lTûPVôL ùLôiÓ ¥Wôuv CpXôRRôp C§p CÚm× CZl×
@TôoUûW YûLlTÓjÕRp. CÚdLôÕ.
• Lôtß úLôo ¥Wôuv@TôoUo (Air core úLôo ùTôÚ°]ôp CÚm× CZl×
transformers): Fig 1þp Lôh¥VYôß Lôtß (iron-loss) HtTÓ¡\Õ. CÕ
úLôo ¥Wôuv@TôoUo Lô¡Rm ApXÕ ¥Wôuv@TôoU¬p JÚ YûL
©[ôv¥d¡]ôp B] EsÇPt\ (hollow) CZlTôÏm.
368 ªuT¦Vô[o þTYo : GXdh¬μVu (NSQF - Revised 2022) R.T. Ex.No. 1.12.98