Page 348 - Electrician -1st Year - TT

Ru U§lÀhÓ úRoÜ (Self-evaluation test) ¾oÜ (Solution)
1 êuß úTv §\u A[ÅhÓdLô]
CWhûP YôhÁhPo Øû\«u tan =
YûWTPj§û] YûWL.
§\û] A[lT§p CWiÓ YôhÁhPo
Øû\«p TYo@úTdPûW LQd¡ÓRp
(Power factor calculation in the two -wattmeter of
measuring power)
¿eLs ØkûRV TôPj§p Lt\Õ úTôX 3
úTv 3 Lm© AûUl©p CWhûP Yôh
ÁhPo Øû\«p ùT\lTÓm ùUôjRj§\u
P = P + P BL CÚdÏm.
T 1 2
CWiÓ YôhÁhPoL°XõÚkÕ ùT\lThP
A[ÅÓL°XõÚkÕ tan þûV ùLôÓdLl
ThÓs[ ãj§Wj§XõÚkÕ ùT\Xôm.
o
= tan —1 8.66 = 83 .27'
TYo @úTdPo (Cos 83 27') = 0.114.
o
tan = ERôWQm 3 (Example 3): Í¡Á úTv
êñQìŠð†ì ðÀM¡ à†ªê½ˆîŠð´‹
C§XõÚkÕ TÞ®u Utßm TYo @úTdPo Fø¬ù Ü÷Mì Þ¬í‚èŠðì Þó‡´
ØRXõVûYLû[ LiP±VXôm. YôhÁhPoèœ º¬ø«ò 600W ñŸÁ‹ 300W
ERôWQm 1 (Example 1): NU²PlThP Ü÷i´è¬÷ 裆´A¡øù. ðÀM¡ ªñ£ˆî
êuß úTv ªuÑt±u EhùNÛjRlTÓm TYo @úTdPo ñŸÁ‹ ªñ£ˆî
§\û] A[®P CûQdLlThP CWiÓ à†ªê½ˆîŠð´‹ Fø¡ ÝAòõŸ¬ø
YôhÁhPoLs Øû\úV 4.5 KW Utßm 3 èí‚A´è.
KWþûV LôhÓ¡u\]. ªuÑt±u TYo ¾oÜ (Solution)
@úTdPûW LiÓ©¥dLÜm.
Total power = P = P + P
¾oÜ (Solution) T 1 2
P = 600W.
1
P = 300W.
tan = 2
P = 600 + 300 = 900W
T
P = 4.5 KW
1
P = 3 KW
2
P + P = 4.5 + 3 = 7.5 KW
1 2
P P = 4.5 3 = 1.5 KW
1 2
tan =
= tan 0.5774 = 30 o
1
0
= tan 0.3464 = 19 6' TYo @úTdPo = Cos 30 = 0.866.
1
o
TYo @úTdPo Cos 19 6' = 0.95
0
AûNuùUuh (Assignment ): êñQìŠð†ì
ERôWQm 2 (Example 2): NU²PlThP Í¡Á úTv ²¬ñJ¡ à†ªê½ˆîŠð´‹
êuß úTv ªuÑt±u EhùNÛjRlTÓm Fø¬ù Ü÷Mì Þ¬í‚èŠð†ì Þó‡´
§\û] A[®P CûQdLlThP CWiÓ õ£† ÁhPoèœ º¬ø«ò 2.5KW ñŸÁ‹ 5KW-
YôhÁhPoLs Øû\úV 4.5 KW Utßm 3 ä 裆´A¡øù.
KWþI LôhÓ¡u\]. CWiPôYRôL (i) Þó‡´ Ü÷i´èÀ‹ «ï˜ñ¬øò£è (+ve)
ùT\lThP A[ÅPô]Õ YôhÁhP¬u Þ¼‚°‹ ªð£¿¶‹ (ii) Þó‡ì£õ¶
ªu]ÝjR Lô«p ©uú]ôd¡ CûQjÕ Ü÷iì£ù¶ YôhÁhP¬¡ I¡ù¿ˆî
ùT\lThPRôÏm. ªuÑt±u TYo Lô«p H¡«ù£‚A ެ툶 ªðøŠð´‹
@úTdPûW LiÓ©¥dLÜm. ªð£¿¶‹ I¡²ŸP¡ TYo @úTdPûW

致H®dLÜm.

328 TYo : GXdh¬μVu (NSQF - Revised 2022) R.T. Ex.No. 1.10.85 & 86