Page 300 - Fashion Design Technology-TP- Hindi

Fig 3

1 - 15 & 1 - 16= 11 cm [Hem width/4 (-1 cm)] Join 16 - 14, 15 - 13 & 3 - 13

Shape 3 - 13 and Shape 9, 4, 14
7, 9, 4, 14, 16, 1, 15, 13, 3, 7 is Trousers Front

Back
1 - 3 c 5 = 7 m ( 2 / p i H ) 0 S q u d e r a o w o r f n m 1 7
17 - 18= 1 cm
1 - 7 9 c 4 = m J 1 - 6 n i o e & 9 e t x n b d c 4 y m & m 2 k r a 0
20 - 21= 20 cm [(W/4 (-1 cm) + Dart] (Dart 3 cm) Square up from 21

21 - 22= 1 cm
20 - 23= 8.5 [W/10 (+ 1.5 cm)]
23 - 24 & 23 - 25= 1.5 cm (Dart 3 cm)
23 - 26= 15 cm (Parallel to 20 - 6 line)

Join 24 - 26, 25 - 26 (Dart)
0 - 27= 22 cm (Hip Level) & mark 28
28 - 29= 4 cm
29 - 30= 26 cm [Hip/4 (+1 cm)] (Seat angle) Shape 18 - 29

284 प रधान - फै शन िडजाइन और ौ ोिगकी - (NSQF संशोिधत 2022) - अ ास 1.11.35